Whakaoti mō v (complex solution)
\left\{\begin{matrix}v=-\frac{y^{t}-2y}{2t}\text{, }&t\neq 0\\v\in \mathrm{C}\text{, }&\left(y=\frac{1}{2}\text{ or }y=0\right)\text{ and }t=0\end{matrix}\right.
Whakaoti mō v
\left\{\begin{matrix}v=-\frac{y^{t}-2y}{2t}\text{, }&\left(t\neq 0\text{ and }y>0\right)\text{ or }\left(y=0\text{ and }t>0\right)\text{ or }\left(t\neq 0\text{ and }y<0\text{ and }Denominator(t)\text{bmod}2=1\right)\\v\in \mathrm{R}\text{, }&y=\frac{1}{2}\text{ and }t=0\end{matrix}\right.
Graph
Tohaina
Kua tāruatia ki te papatopenga
vt+\frac{1}{2}y^{t}=y
Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.
vt=y-\frac{1}{2}y^{t}
Tangohia te \frac{1}{2}y^{t} mai i ngā taha e rua.
tv=-\frac{y^{t}}{2}+y
He hanga arowhānui tō te whārite.
\frac{tv}{t}=\frac{-\frac{y^{t}}{2}+y}{t}
Whakawehea ngā taha e rua ki te t.
v=\frac{-\frac{y^{t}}{2}+y}{t}
Mā te whakawehe ki te t ka wetekia te whakareanga ki te t.
vt+\frac{1}{2}y^{t}=y
Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.
vt=y-\frac{1}{2}y^{t}
Tangohia te \frac{1}{2}y^{t} mai i ngā taha e rua.
tv=-\frac{y^{t}}{2}+y
He hanga arowhānui tō te whārite.
\frac{tv}{t}=\frac{-\frac{y^{t}}{2}+y}{t}
Whakawehea ngā taha e rua ki te t.
v=\frac{-\frac{y^{t}}{2}+y}{t}
Mā te whakawehe ki te t ka wetekia te whakareanga ki te t.
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