Whakaoti i te y=axsqrt{b}

$$y = a x \sqrt { b }$$

Whakaoti mō a (complex solution)

$$\left\{\begin{matrix}a=\frac{b^{-\frac{1}{2}}y}{x}\text{, }&b\neq 0\text{ and }x\neq 0\\a\in \mathrm{C}\text{, }&\left(b=0\text{ or }x=0\right)\text{ and }y=0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$ax\sqrt{b}=y$$

He hanga arowhānui tō te whārite.

$$\sqrt{b}xa=y$$

Whakawehea ngā taha e rua ki te x\sqrt{b}.

$$\frac{\sqrt{b}xa}{\sqrt{b}x}=\frac{y}{\sqrt{b}x}$$

Mā te whakawehe ki te x\sqrt{b} ka wetekia te whakareanga ki te x\sqrt{b}.

$$a=\frac{y}{\sqrt{b}x}$$

Whakawehe y ki te x\sqrt{b}.

$$a=\frac{b^{-\frac{1}{2}}y}{x}$$

Whakaoti mō a

$$\left\{\begin{matrix}a=\frac{y}{\sqrt{b}x}\text{, }&x\neq 0\text{ and }b>0\\a\in \mathrm{R}\text{, }&\left(y=0\text{ and }x=0\text{ and }b>0\right)\text{ or }\left(b=0\text{ and }y=0\right)\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$ax\sqrt{b}=y$$

He hanga arowhānui tō te whārite.

$$\sqrt{b}xa=y$$

Whakawehea ngā taha e rua ki te x\sqrt{b}.

$$\frac{\sqrt{b}xa}{\sqrt{b}x}=\frac{y}{\sqrt{b}x}$$

Mā te whakawehe ki te x\sqrt{b} ka wetekia te whakareanga ki te x\sqrt{b}.

$$a=\frac{y}{\sqrt{b}x}$$

Whakaoti mō b

$$\left\{\begin{matrix}b=\left(\frac{y}{ax}\right)^{2}\text{, }&x\neq 0\text{ and }a\neq 0\text{ and }\left(a<0\text{ or }x<0\text{ or }y\geq 0\right)\text{ and }\left(x<0\text{ or }a>0\text{ or }y\leq 0\right)\text{ and }\left(a<0\text{ or }x>0\text{ or }y\leq 0\right)\text{ and }\left(x>0\text{ or }a>0\text{ or }y\geq 0\right)\\b\geq 0\text{, }&\left(y=0\text{ and }x=0\right)\text{ or }\left(x\neq 0\text{ and }y=0\text{ and }a=0\right)\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Pūtake

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$ax\sqrt{b}=y$$

Whakawehea ngā taha e rua ki te ax.

$$\frac{ax\sqrt{b}}{ax}=\frac{y}{ax}$$

Mā te whakawehe ki te ax ka wetekia te whakareanga ki te ax.

$$\sqrt{b}=\frac{y}{ax}$$

Pūruatia ngā taha e rua o te whārite.

$$b=\frac{y^{2}}{\left(ax\right)^{2}}$$

Whakaoti mō b (complex solution)

$$\left\{\begin{matrix}b=\left(\frac{y}{ax}\right)^{2}\text{, }&x\neq 0\text{ and }a\neq 0\text{ and }\left(|-arg(y)+arg(\sqrt{\left(\frac{y}{ax}\right)^{2}}ax)|<\pi \text{ or }y=0\right)\\b\in \mathrm{C}\text{, }&\left(x=0\text{ or }a=0\right)\text{ and }y=0\end{matrix}\right.$$