Whakaoti i te y=a(x+1

$$y = a ( x + 1$$

Whakaoti mō a (complex solution)

$$\left\{\begin{matrix}a=\frac{y}{x+1}\text{, }&x\neq -1\\a\in \mathrm{C}\text{, }&y=0\text{ and }x=-1\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te a ki te x+1.

$$y=ax+a$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$ax+a=y$$

Pahekotia ngā kīanga tau katoa e whai ana i te a.

$$\left(x+1\right)a=y$$

Whakawehea ngā taha e rua ki te x+1.

$$\frac{\left(x+1\right)a}{x+1}=\frac{y}{x+1}$$

Mā te whakawehe ki te x+1 ka wetekia te whakareanga ki te x+1.

$$a=\frac{y}{x+1}$$

Whakaoti mō x (complex solution)

$$\left\{\begin{matrix}x=\frac{y}{a}-1\text{, }&a\neq 0\\x\in \mathrm{C}\text{, }&y=0\text{ and }a=0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te a ki te x+1.

$$y=ax+a$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$ax+a=y$$

Tangohia te a mai i ngā taha e rua.

$$ax=y-a$$

Whakawehea ngā taha e rua ki te a.

$$\frac{ax}{a}=\frac{y-a}{a}$$

Mā te whakawehe ki te a ka wetekia te whakareanga ki te a.

$$x=\frac{y-a}{a}$$

Whakawehe y-a ki te a.

$$x=\frac{y}{a}-1$$

Whakaoti mō a

$$\left\{\begin{matrix}a=\frac{y}{x+1}\text{, }&x\neq -1\\a\in \mathrm{R}\text{, }&y=0\text{ and }x=-1\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te a ki te x+1.

$$y=ax+a$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$ax+a=y$$

Pahekotia ngā kīanga tau katoa e whai ana i te a.

$$\left(x+1\right)a=y$$

Whakawehea ngā taha e rua ki te x+1.

$$\frac{\left(x+1\right)a}{x+1}=\frac{y}{x+1}$$

Mā te whakawehe ki te x+1 ka wetekia te whakareanga ki te x+1.

$$a=\frac{y}{x+1}$$

Whakaoti mō x

$$\left\{\begin{matrix}x=\frac{y}{a}-1\text{, }&a\neq 0\\x\in \mathrm{R}\text{, }&y=0\text{ and }a=0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te a ki te x+1.

$$y=ax+a$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$ax+a=y$$

Tangohia te a mai i ngā taha e rua.

$$ax=y-a$$

Whakawehea ngā taha e rua ki te a.

$$\frac{ax}{a}=\frac{y-a}{a}$$

Mā te whakawehe ki te a ka wetekia te whakareanga ki te a.

$$x=\frac{y-a}{a}$$

Whakawehe y-a ki te a.

$$x=\frac{y}{a}-1$$