Whakaoti i te y=4+2/1-x

$$y = 4 + \frac { 2 } { 1 - x }$$

Whakaoti mō x

$$x=-\frac{6-y}{y-4}$$

$$y\neq 4$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe x ki 1 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te -x+1.

$$y\left(-x+1\right)=\left(-x+1\right)\times 4+2$$

Whakamahia te āhuatanga tohatoha hei whakarea te y ki te -x+1.

$$-yx+y=\left(-x+1\right)\times 4+2$$

Whakamahia te āhuatanga tohatoha hei whakarea te -x+1 ki te 4.

$$-yx+y=-4x+4+2$$

Tāpirihia te 4 ki te 2, ka 6.

$$-yx+y=-4x+6$$

Me tāpiri te 4x ki ngā taha e rua.

$$-yx+y+4x=6$$

Tangohia te y mai i ngā taha e rua.

$$-yx+4x=6-y$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(-y+4\right)x=6-y$$

He hanga arowhānui tō te whārite.

$$\left(4-y\right)x=6-y$$

Whakawehea ngā taha e rua ki te -y+4.

$$\frac{\left(4-y\right)x}{4-y}=\frac{6-y}{4-y}$$

Mā te whakawehe ki te -y+4 ka wetekia te whakareanga ki te -y+4.

$$x=\frac{6-y}{4-y}$$

Tē taea kia ōrite te tāupe x ki 1.

$$x=\frac{6-y}{4-y}\text{, }x\neq 1$$

Whakaoti mō y

$$y=-\frac{2\left(2x-3\right)}{1-x}$$

$$x\neq 1$$