Whakaoti i te y=2pisqrt{L/32}

$$y = 2 \pi \sqrt { \frac { L } { 32 } }$$

Whakaoti mō L

$$L=8\times \left(\frac{y}{\pi }\right)^{2}$$

$$y\geq 0$$

Ngā Upane mō te Whakaoti Whārite Pūtake

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$2\pi \sqrt{\frac{L}{32}}=y$$

Whakawehea ngā taha e rua ki te 2\pi .

$$\frac{2\pi \sqrt{\frac{1}{32}L}}{2\pi }=\frac{y}{2\pi }$$

Mā te whakawehe ki te 2\pi ka wetekia te whakareanga ki te 2\pi .

$$\sqrt{\frac{1}{32}L}=\frac{y}{2\pi }$$

Pūruatia ngā taha e rua o te whārite.

$$\frac{1}{32}L=\frac{y^{2}}{4\pi ^{2}}$$

Me whakarea ngā taha e rua ki te 32.

$$\frac{\frac{1}{32}L}{\frac{1}{32}}=\frac{y^{2}}{\frac{1}{32}\times 4\pi ^{2}}$$

Mā te whakawehe ki te \frac{1}{32} ka wetekia te whakareanga ki te \frac{1}{32}.

$$L=\frac{y^{2}}{\frac{1}{32}\times 4\pi ^{2}}$$

Whakawehe \frac{y^{2}}{4\pi ^{2}} ki te \frac{1}{32} mā te whakarea \frac{y^{2}}{4\pi ^{2}} ki te tau huripoki o \frac{1}{32}.

$$L=\frac{8y^{2}}{\pi ^{2}}$$

Whakaoti mō y

$$y=\frac{\pi \sqrt{2L}}{4}$$

$$L\geq 0$$