Whakaoti i te y=05(x+2.4)^2+0.8(2x+7.65)

$$y = 05 ( x + 2.4 ) ^ { 2 } + 0.8 ( 2 x + 7.65 )$$

Whakaoti mō x

$$x=\frac{5y}{8}-3.825$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia te 0 ki te 5, ka 0.

$$y=0\left(x+2.4\right)^{2}+0.8\left(2x+7.65\right)$$

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(x+2.4\right)^{2}.

$$y=0\left(x^{2}+4.8x+5.76\right)+0.8\left(2x+7.65\right)$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$y=0+0.8\left(2x+7.65\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 0.8 ki te 2x+7.65.

$$y=0+1.6x+6.12$$

Tāpirihia te 0 ki te 6.12, ka 6.12.

$$y=6.12+1.6x$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$6.12+1.6x=y$$

Tangohia te 6.12 mai i ngā taha e rua.

$$1.6x=y-6.12$$

Whakawehea ngā taha e rua o te whārite ki te 1.6, he ōrite ki te whakarea i ngā taha e rua ki te tau huripoki o te hautanga.

$$\frac{1.6x}{1.6}=\frac{y-6.12}{1.6}$$

Mā te whakawehe ki te 1.6 ka wetekia te whakareanga ki te 1.6.

$$x=\frac{y-6.12}{1.6}$$

Whakawehe y-6.12 ki te 1.6 mā te whakarea y-6.12 ki te tau huripoki o 1.6.

$$x=\frac{5y}{8}-3.825$$

Whakaoti mō y

$$y=\frac{8x}{5}+6.12$$

Ngā Upane Otinga

Whakareatia te 0 ki te 5, ka 0.

$$y=0\left(x+2.4\right)^{2}+0.8\left(2x+7.65\right)$$

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(x+2.4\right)^{2}.

$$y=0\left(x^{2}+4.8x+5.76\right)+0.8\left(2x+7.65\right)$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$y=0+0.8\left(2x+7.65\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 0.8 ki te 2x+7.65.

$$y=0+1.6x+6.12$$

Tāpirihia te 0 ki te 6.12, ka 6.12.

$$y=6.12+1.6x$$