Whakaoti i te y=-sqrt{x+2}-3

$$y = - \sqrt { x + 2 } - 3$$

Whakaoti mō x

$$x=\left(y+3\right)^{2}-2$$

$$-\left(y+3\right)\geq 0$$

Ngā Upane mō te Whakaoti Whārite Pūtake

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$-\sqrt{x+2}-3=y$$

Me tāpiri te 3 ki ngā taha e rua.

$$-\sqrt{x+2}=y+3$$

Whakawehea ngā taha e rua ki te -1.

$$\frac{-\sqrt{x+2}}{-1}=\frac{y+3}{-1}$$

Mā te whakawehe ki te -1 ka wetekia te whakareanga ki te -1.

$$\sqrt{x+2}=\frac{y+3}{-1}$$

Whakawehe y+3 ki te -1.

$$\sqrt{x+2}=-\left(y+3\right)$$

Pūruatia ngā taha e rua o te whārite.

$$x+2=\left(y+3\right)^{2}$$

Me tango 2 mai i ngā taha e rua o te whārite.

$$x+2-2=\left(y+3\right)^{2}-2$$

Mā te tango i te 2 i a ia ake anō ka toe ko te 0.

$$x=\left(y+3\right)^{2}-2$$

Whakaoti mō x (complex solution)

$$x=\left(y+3\right)^{2}-2$$

$$y=-3\text{ or }arg(y+3)\geq \pi$$

Whakaoti mō y (complex solution)

$$y=-\left(\sqrt{x+2}+3\right)$$

Whakaoti mō y

$$y=-\left(\sqrt{x+2}+3\right)$$

$$x\geq -2$$