Whakaoti i te y=(x-a)sqrt{x}

$$y = ( x - a ) \sqrt { x }$$

Whakaoti mō a

$$\left\{\begin{matrix}a=x-\frac{y}{\sqrt{x}}\text{, }&x>0\\a\in \mathrm{R}\text{, }&x=0\text{ and }y=0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te x-a ki te \sqrt{x}.

$$y=x\sqrt{x}-a\sqrt{x}$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$x\sqrt{x}-a\sqrt{x}=y$$

Tangohia te x\sqrt{x} mai i ngā taha e rua.

$$-a\sqrt{x}=y-x\sqrt{x}$$

Whakaraupapatia anō ngā kīanga tau.

$$-\sqrt{x}a=-\sqrt{x}x+y$$

He hanga arowhānui tō te whārite.

$$\left(-\sqrt{x}\right)a=-\sqrt{x}x+y$$

Whakawehea ngā taha e rua ki te -\sqrt{x}.

$$\frac{\left(-\sqrt{x}\right)a}{-\sqrt{x}}=\frac{y-x^{\frac{3}{2}}}{-\sqrt{x}}$$

Mā te whakawehe ki te -\sqrt{x} ka wetekia te whakareanga ki te -\sqrt{x}.

$$a=\frac{y-x^{\frac{3}{2}}}{-\sqrt{x}}$$

Whakawehe -x^{\frac{3}{2}}+y ki te -\sqrt{x}.

$$a=x-\frac{y}{\sqrt{x}}$$