Whakaoti i te y=(4t-1)(3t-2)^-1

$$y = ( 4 t - 1 ) ( 3 t - 2 ) ^ { - 1 }$$

Whakaoti mō t

$$t=-\frac{1-2y}{3y-4}$$

$$y\neq \frac{4}{3}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 4t-1 ki te \left(3t-2\right)^{-1}.

$$y=4t\left(3t-2\right)^{-1}-\left(3t-2\right)^{-1}$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$4t\left(3t-2\right)^{-1}-\left(3t-2\right)^{-1}=y$$

Whakaraupapatia anō ngā kīanga tau.

$$4\times \frac{1}{3t-2}t-\frac{1}{3t-2}=y$$

Tē taea kia ōrite te tāupe t ki \frac{2}{3} nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te 3t-2.

$$4\times 1t-1=y\left(3t-2\right)$$

Mahia ngā whakarea.

$$4t-1=y\left(3t-2\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te y ki te 3t-2.

$$4t-1=3yt-2y$$

Tangohia te 3yt mai i ngā taha e rua.

$$4t-1-3yt=-2y$$

Me tāpiri te 1 ki ngā taha e rua.

$$4t-3yt=-2y+1$$

Pahekotia ngā kīanga tau katoa e whai ana i te t.

$$\left(4-3y\right)t=-2y+1$$

He hanga arowhānui tō te whārite.

$$\left(4-3y\right)t=1-2y$$

Whakawehea ngā taha e rua ki te 4-3y.

$$\frac{\left(4-3y\right)t}{4-3y}=\frac{1-2y}{4-3y}$$

Mā te whakawehe ki te 4-3y ka wetekia te whakareanga ki te 4-3y.

$$t=\frac{1-2y}{4-3y}$$

Tē taea kia ōrite te tāupe t ki \frac{2}{3}.

$$t=\frac{1-2y}{4-3y}\text{, }t\neq \frac{2}{3}$$

Whakaoti mō y

$$y=-\frac{1-4t}{3t-2}$$

$$t\neq \frac{2}{3}$$