Whakaoti mō x
x=y^{2}+16
y\geq 0
Whakaoti mō x (complex solution)
x=y^{2}+16
arg(y)<\pi \text{ or }y=0
Whakaoti mō y
y=\sqrt{x-16}
x\geq 16
Graph
Tohaina
Kua tāruatia ki te papatopenga
\sqrt{x-16}=y
Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.
x-16=y^{2}
Pūruatia ngā taha e rua o te whārite.
x-16-\left(-16\right)=y^{2}-\left(-16\right)
Me tāpiri 16 ki ngā taha e rua o te whārite.
x=y^{2}-\left(-16\right)
Mā te tango i te -16 i a ia ake anō ka toe ko te 0.
x=y^{2}+16
Tango -16 mai i y^{2}.
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