Whakaoti i te y=sqrt{4-2x}

$$y = \sqrt { 4 - 2 x }$$

Whakaoti mō x

$$x=-\frac{y^{2}}{2}+2$$

$$y\geq 0$$

Ngā Upane mō te Whakaoti Whārite Pūtake

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$\sqrt{4-2x}=y$$

Pūruatia ngā taha e rua o te whārite.

$$-2x+4=y^{2}$$

Me tango 4 mai i ngā taha e rua o te whārite.

$$-2x+4-4=y^{2}-4$$

Mā te tango i te 4 i a ia ake anō ka toe ko te 0.

$$-2x=y^{2}-4$$

Whakawehea ngā taha e rua ki te -2.

$$\frac{-2x}{-2}=\frac{y^{2}-4}{-2}$$

Mā te whakawehe ki te -2 ka wetekia te whakareanga ki te -2.

$$x=\frac{y^{2}-4}{-2}$$

Whakawehe y^{2}-4 ki te -2.

$$x=-\frac{y^{2}}{2}+2$$

Whakaoti mō x (complex solution)

$$x=-\frac{y^{2}}{2}+2$$

$$arg(y)<\pi \text{ or }y=0$$

Whakaoti mō y

$$y=\sqrt{4-2x}$$

$$x\leq 2$$