Whakaoti i te y=sqrt{3x-12}

$$y = \sqrt { 3 x - 12 }$$

Whakaoti mō x

$$x=\frac{y^{2}+12}{3}$$

$$y\geq 0$$

Ngā Upane mō te Whakaoti Whārite Pūtake

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$\sqrt{3x-12}=y$$

Pūruatia ngā taha e rua o te whārite.

$$3x-12=y^{2}$$

Me tāpiri 12 ki ngā taha e rua o te whārite.

$$3x-12-\left(-12\right)=y^{2}-\left(-12\right)$$

Mā te tango i te -12 i a ia ake anō ka toe ko te 0.

$$3x=y^{2}-\left(-12\right)$$

Tango -12 mai i y^{2}.

$$3x=y^{2}+12$$

Whakawehea ngā taha e rua ki te 3.

$$\frac{3x}{3}=\frac{y^{2}+12}{3}$$

Mā te whakawehe ki te 3 ka wetekia te whakareanga ki te 3.

$$x=\frac{y^{2}+12}{3}$$

Whakawehe y^{2}+12 ki te 3.

$$x=\frac{y^{2}}{3}+4$$

Whakaoti mō x (complex solution)

$$x=\frac{y^{2}+12}{3}$$

$$arg(y)<\pi \text{ or }y=0$$

Whakaoti mō y (complex solution)

$$y=\sqrt{3\left(x-4\right)}$$

Whakaoti mō y

$$y=\sqrt{3\left(x-4\right)}$$

$$x\geq 4$$