Whakaoti i te y=sqrt{3-4x}

$$y = \sqrt { 3 - 4 x }$$

Whakaoti mō x

$$x=\frac{3-y^{2}}{4}$$

$$y\geq 0$$

Ngā Upane mō te Whakaoti Whārite Pūtake

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$\sqrt{3-4x}=y$$

Pūruatia ngā taha e rua o te whārite.

$$-4x+3=y^{2}$$

Me tango 3 mai i ngā taha e rua o te whārite.

$$-4x+3-3=y^{2}-3$$

Mā te tango i te 3 i a ia ake anō ka toe ko te 0.

$$-4x=y^{2}-3$$

Whakawehea ngā taha e rua ki te -4.

$$\frac{-4x}{-4}=\frac{y^{2}-3}{-4}$$

Mā te whakawehe ki te -4 ka wetekia te whakareanga ki te -4.

$$x=\frac{y^{2}-3}{-4}$$

Whakawehe y^{2}-3 ki te -4.

$$x=\frac{3-y^{2}}{4}$$

Whakaoti mō x (complex solution)

$$x=\frac{3-y^{2}}{4}$$

$$arg(y)<\pi \text{ or }y=0$$

Whakaoti mō y

$$y=\sqrt{3-4x}$$

$$x\leq \frac{3}{4}$$