Whakaoti i te y=sqrt{1-5x}

$$y = \sqrt { 1 - 5 x }$$

Whakaoti mō x

$$x=\frac{1-y^{2}}{5}$$

$$y\geq 0$$

Ngā Upane mō te Whakaoti Whārite Pūtake

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$\sqrt{1-5x}=y$$

Pūruatia ngā taha e rua o te whārite.

$$-5x+1=y^{2}$$

Me tango 1 mai i ngā taha e rua o te whārite.

$$-5x+1-1=y^{2}-1$$

Mā te tango i te 1 i a ia ake anō ka toe ko te 0.

$$-5x=y^{2}-1$$

Whakawehea ngā taha e rua ki te -5.

$$\frac{-5x}{-5}=\frac{y^{2}-1}{-5}$$

Mā te whakawehe ki te -5 ka wetekia te whakareanga ki te -5.

$$x=\frac{y^{2}-1}{-5}$$

Whakawehe y^{2}-1 ki te -5.

$$x=\frac{1-y^{2}}{5}$$

Whakaoti mō x (complex solution)

$$x=\frac{1-y^{2}}{5}$$

$$arg(y)<\pi \text{ or }y=0$$

Whakaoti mō y

$$y=\sqrt{1-5x}$$

$$x\leq \frac{1}{5}$$