Whakaoti i te y=x+1/2-x

$$y = \frac { x + 1 } { 2 - x }$$

Whakaoti mō x

$$x=\frac{2y-1}{y+1}$$

$$y\neq -1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe x ki 2 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te -x+2.

$$y\left(-x+2\right)=x+1$$

Whakamahia te āhuatanga tohatoha hei whakarea te y ki te -x+2.

$$-yx+2y=x+1$$

Tangohia te x mai i ngā taha e rua.

$$-yx+2y-x=1$$

Tangohia te 2y mai i ngā taha e rua.

$$-yx-x=1-2y$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(-y-1\right)x=1-2y$$

Whakawehea ngā taha e rua ki te -y-1.

$$\frac{\left(-y-1\right)x}{-y-1}=\frac{1-2y}{-y-1}$$

Mā te whakawehe ki te -y-1 ka wetekia te whakareanga ki te -y-1.

$$x=\frac{1-2y}{-y-1}$$

Whakawehe 1-2y ki te -y-1.

$$x=-\frac{1-2y}{y+1}$$

Tē taea kia ōrite te tāupe x ki 2.

$$x=-\frac{1-2y}{y+1}\text{, }x\neq 2$$

Whakaoti mō y

$$y=\frac{x+1}{2-x}$$

$$x\neq 2$$