Whakaoti i te y=4ac-b^2/4a

$$y = \frac { 4 a c - b ^ { 2 } } { 4 a }$$

Whakaoti mō a

$$\left\{\begin{matrix}a=-\frac{b^{2}}{4\left(y-c\right)}\text{, }&b\neq 0\text{ and }y\neq c\\a\neq 0\text{, }&b=0\text{ and }y=c\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe a ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te 4a.

$$y\times 4a=4ac-b^{2}$$

Tangohia te 4ac mai i ngā taha e rua.

$$y\times 4a-4ac=-b^{2}$$

Pahekotia ngā kīanga tau katoa e whai ana i te a.

$$\left(y\times 4-4c\right)a=-b^{2}$$

He hanga arowhānui tō te whārite.

$$\left(4y-4c\right)a=-b^{2}$$

Whakawehea ngā taha e rua ki te 4y-4c.

$$\frac{\left(4y-4c\right)a}{4y-4c}=-\frac{b^{2}}{4y-4c}$$

Mā te whakawehe ki te 4y-4c ka wetekia te whakareanga ki te 4y-4c.

$$a=-\frac{b^{2}}{4y-4c}$$

Whakawehe -b^{2} ki te 4y-4c.

$$a=-\frac{b^{2}}{4\left(y-c\right)}$$

Tē taea kia ōrite te tāupe a ki 0.

$$a=-\frac{b^{2}}{4\left(y-c\right)}\text{, }a\neq 0$$

Whakaoti mō b (complex solution)

$$b=-2\sqrt{a}\sqrt{c-y}$$

$$b=2\sqrt{a}\sqrt{c-y}\text{, }a\neq 0$$

Whakaoti mō b

$$b=2\sqrt{a\left(c-y\right)}$$

$$b=-2\sqrt{a\left(c-y\right)}\text{, }\left(a<0\text{ or }y\leq c\right)\text{ and }\left(a>0\text{ or }y\geq c\right)\text{ and }a\neq 0$$