Whakaoti i te y=1/2sqrt{x-1}

$$y = \frac { 1 } { 2 } \sqrt { x - 1 }$$

Whakaoti mō x

$$x=4y^{2}+1$$

$$y\geq 0$$

Ngā Upane mō te Whakaoti Whārite Pūtake

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$\frac{1}{2}\sqrt{x-1}=y$$

Me whakarea ngā taha e rua ki te 2.

$$\frac{\frac{1}{2}\sqrt{x-1}}{\frac{1}{2}}=\frac{y}{\frac{1}{2}}$$

Mā te whakawehe ki te \frac{1}{2} ka wetekia te whakareanga ki te \frac{1}{2}.

$$\sqrt{x-1}=\frac{y}{\frac{1}{2}}$$

Whakawehe y ki te \frac{1}{2} mā te whakarea y ki te tau huripoki o \frac{1}{2}.

$$\sqrt{x-1}=2y$$

Pūruatia ngā taha e rua o te whārite.

$$x-1=4y^{2}$$

Me tāpiri 1 ki ngā taha e rua o te whārite.

$$x-1-\left(-1\right)=4y^{2}-\left(-1\right)$$

Mā te tango i te -1 i a ia ake anō ka toe ko te 0.

$$x=4y^{2}-\left(-1\right)$$

Tango -1 mai i 4y^{2}.

$$x=4y^{2}+1$$

Whakaoti mō x (complex solution)

$$x=4y^{2}+1$$

$$arg(y)<\pi \text{ or }y=0$$

Whakaoti mō y (complex solution)

$$y=\frac{\sqrt{x-1}}{2}$$

Whakaoti mō y

$$y=\frac{\sqrt{x-1}}{2}$$

$$x\geq 1$$