Whakaoti i te y=1/2sqrt{x+1}-5

$$y = \frac { 1 } { 2 } \sqrt { x + 1 } - 5$$

Whakaoti mō x

$$x=\left(2y+9\right)\left(2y+11\right)$$

$$2y+10\geq 0$$

Ngā Upane mō te Whakaoti Whārite Pūtake

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$\frac{1}{2}\sqrt{x+1}-5=y$$

Me tāpiri te 5 ki ngā taha e rua.

$$\frac{1}{2}\sqrt{x+1}=y+5$$

Me whakarea ngā taha e rua ki te 2.

$$\frac{\frac{1}{2}\sqrt{x+1}}{\frac{1}{2}}=\frac{y+5}{\frac{1}{2}}$$

Mā te whakawehe ki te \frac{1}{2} ka wetekia te whakareanga ki te \frac{1}{2}.

$$\sqrt{x+1}=\frac{y+5}{\frac{1}{2}}$$

Whakawehe y+5 ki te \frac{1}{2} mā te whakarea y+5 ki te tau huripoki o \frac{1}{2}.

$$\sqrt{x+1}=2y+10$$

Pūruatia ngā taha e rua o te whārite.

$$x+1=4\left(y+5\right)^{2}$$

Me tango 1 mai i ngā taha e rua o te whārite.

$$x+1-1=4\left(y+5\right)^{2}-1$$

Mā te tango i te 1 i a ia ake anō ka toe ko te 0.

$$x=4\left(y+5\right)^{2}-1$$

Tango 1 mai i 4\left(5+y\right)^{2}.

$$x=4y^{2}+40y+99$$

Whakaoti mō x (complex solution)

$$x=\left(2y+9\right)\left(2y+11\right)$$

$$y=-5\text{ or }arg(2y+10)<\pi$$

Whakaoti mō y (complex solution)

$$y=\frac{\sqrt{x+1}-10}{2}$$

Whakaoti mō y

$$y=\frac{\sqrt{x+1}-10}{2}$$

$$x\geq -1$$