Whakaoti i te y=-2/2sqrt{x+2}+4

$$y = \frac { - 2 } { 2 } \sqrt { x + 2 } + 4$$

Whakaoti mō x

$$x=\left(4-y\right)^{2}-2$$

$$4-y\geq 0$$

Ngā Upane mō te Whakaoti Whārite Pūtake

Whakawehea te -2 ki te 2, kia riro ko -1.

$$y=-\sqrt{x+2}+4$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$-\sqrt{x+2}+4=y$$

Tangohia te 4 mai i ngā taha e rua.

$$-\sqrt{x+2}=y-4$$

Whakawehea ngā taha e rua ki te -1.

$$\frac{-\sqrt{x+2}}{-1}=\frac{y-4}{-1}$$

Mā te whakawehe ki te -1 ka wetekia te whakareanga ki te -1.

$$\sqrt{x+2}=\frac{y-4}{-1}$$

Whakawehe y-4 ki te -1.

$$\sqrt{x+2}=4-y$$

Pūruatia ngā taha e rua o te whārite.

$$x+2=\left(4-y\right)^{2}$$

Me tango 2 mai i ngā taha e rua o te whārite.

$$x+2-2=\left(4-y\right)^{2}-2$$

Mā te tango i te 2 i a ia ake anō ka toe ko te 0.

$$x=\left(4-y\right)^{2}-2$$

Whakaoti mō x (complex solution)

$$x=\left(4-y\right)^{2}-2$$

$$y=4\text{ or }arg(4-y)<\pi$$

Whakaoti mō y (complex solution)

$$y=-\sqrt{x+2}+4$$

Whakaoti mō y

$$y=-\sqrt{x+2}+4$$

$$x\geq -2$$