Whakaoti i te y=-1/x-2+2

$$y = \frac { - 1 } { x - 2 } + 2$$

Whakaoti mō x

$$x=-\frac{5-2y}{y-2}$$

$$y\neq 2$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe x ki 2 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te x-2.

$$y\left(x-2\right)=-1+\left(x-2\right)\times 2$$

Whakamahia te āhuatanga tohatoha hei whakarea te y ki te x-2.

$$yx-2y=-1+\left(x-2\right)\times 2$$

Whakamahia te āhuatanga tohatoha hei whakarea te x-2 ki te 2.

$$yx-2y=-1+2x-4$$

Tangohia te 4 i te -1, ka -5.

$$yx-2y=-5+2x$$

Tangohia te 2x mai i ngā taha e rua.

$$yx-2y-2x=-5$$

Me tāpiri te 2y ki ngā taha e rua.

$$yx-2x=-5+2y$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(y-2\right)x=-5+2y$$

He hanga arowhānui tō te whārite.

$$\left(y-2\right)x=2y-5$$

Whakawehea ngā taha e rua ki te y-2.

$$\frac{\left(y-2\right)x}{y-2}=\frac{2y-5}{y-2}$$

Mā te whakawehe ki te y-2 ka wetekia te whakareanga ki te y-2.

$$x=\frac{2y-5}{y-2}$$

Tē taea kia ōrite te tāupe x ki 2.

$$x=\frac{2y-5}{y-2}\text{, }x\neq 2$$

Whakaoti mō y

$$y=-\frac{5-2x}{x-2}$$

$$x\neq 2$$