Whakaoti i te y+2=-1/3(x+4)

$$y + 2 = - \frac { 1 } { 3 } ( x + 4 )$$

Whakaoti mō x

$$x=-3y-10$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te -\frac{1}{3} ki te x+4.

$$y+2=-\frac{1}{3}x-\frac{4}{3}$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$-\frac{1}{3}x-\frac{4}{3}=y+2$$

Me tāpiri te \frac{4}{3} ki ngā taha e rua.

$$-\frac{1}{3}x=y+2+\frac{4}{3}$$

Tāpirihia te 2 ki te \frac{4}{3}, ka \frac{10}{3}.

$$-\frac{1}{3}x=y+\frac{10}{3}$$

Me whakarea ngā taha e rua ki te -3.

$$\frac{-\frac{1}{3}x}{-\frac{1}{3}}=\frac{y+\frac{10}{3}}{-\frac{1}{3}}$$

Mā te whakawehe ki te -\frac{1}{3} ka wetekia te whakareanga ki te -\frac{1}{3}.

$$x=\frac{y+\frac{10}{3}}{-\frac{1}{3}}$$

Whakawehe y+\frac{10}{3} ki te -\frac{1}{3} mā te whakarea y+\frac{10}{3} ki te tau huripoki o -\frac{1}{3}.

$$x=-3y-10$$

Whakaoti mō y

$$y=\frac{-x-10}{3}$$

Ngā Upane Otinga

Whakamahia te āhuatanga tohatoha hei whakarea te -\frac{1}{3} ki te x+4.

$$y+2=-\frac{1}{3}x-\frac{4}{3}$$

Tangohia te 2 mai i ngā taha e rua.

$$y=-\frac{1}{3}x-\frac{4}{3}-2$$

Tangohia te 2 i te -\frac{4}{3}, ka -\frac{10}{3}.

$$y=-\frac{1}{3}x-\frac{10}{3}$$