Whakaoti i te xyz=64 | Kairarau Microsoft

x y z = 64

Whakaoti mō x

x = \frac{6 4}{y z}

z \neq = 0 and y \neq = 0

Whakaoti mō y

y = \frac{6 4}{x z}

z \neq = 0 and x \neq = 0

Pātaitai

Linear Equation

x y z = 64

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Step-by-step method of solving Linear Equations.

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Ngā Raru Ōrite mai i te Rapu Tukutuku

x^{2} + y^{2} + z^{2} = 4, z \geq 4 .

https://math.stackexchange.com/q/2682201

Note that

(1)

hold since

x y, x z, y z

are antisymmetric function on the domain, indeed, for example, at each point xy in the I quadrant correspond -xy in th II and so on

(2)

hold since

x^{2}, y^{2}, z^{2}

...

Compute

∭_{R} 6 z d V .

https://math.stackexchange.com/questions/2653957/compute-iiint-r-6z-dv/2653964

Yes, it seems absolutely correct as set up and also as calculation. To check the result note that the given integral is equal to

6 \cdot z_{G} \cdot V = 6 \cdot \frac{5}{4} \cdot \frac{2 5}{6} = \frac{1 2 5}{4}

...

Finding tangent plane to a surface

https://math.stackexchange.com/questions/2943591/finding-tangent-plane-to-a-surface

Assuming you mean your tangent plane should be normal to the given line, you are looking for a point where the normal to the surface (i.e., the gradient) is parallel to the direction vector of the ...

Examples of a group

G

with a non-trivial homomorphism

f : G \to Z (G)

https://math.stackexchange.com/questions/2692367/examples-of-a-group-g-with-a-non-trivial-homomorphism-fg-to-zg/2692379

For any finite field

F

and any

n

, you can consider

G : = G L_{n}

, whose center is

F^{\times} I

where

I

is the identity matrix. Now, take the determinant as your homomorphism.

Help understanding the definition of tangent vector or tangent plane?

https://math.stackexchange.com/q/12331

This is intended as a complement to Alex Bartel's answer. (1) Consider the 2D case given by

x = x (t)

y = y (t)

. Here is a graph of a parametrized function with

(x (t_{0}), y (t_{0}))

(in red) and

(x (t_{0} + δ), y (t_{0} + δ))

...

Question about level set.

https://math.stackexchange.com/q/1219881

In general, such a line will be parametrized by

x = a z + 2, y = b z + 5

unless the line lies on the plane

z = 0

, which is easy to see not to be the case. In a more general case, the linear ...

Tohaina

Kua tāruatia ki te papatopenga

yzx=64

He hanga arowhānui tō te whārite.

\frac{yzx}{yz}=\frac{64}{yz}

Whakawehea ngā taha e rua ki te yz.

x=\frac{64}{yz}

Mā te whakawehe ki te yz ka wetekia te whakareanga ki te yz.

xzy=64

He hanga arowhānui tō te whārite.

\frac{xzy}{xz}=\frac{64}{xz}

Whakawehea ngā taha e rua ki te xz.

y=\frac{64}{xz}

Mā te whakawehe ki te xz ka wetekia te whakareanga ki te xz.

Ngā Tauira

whārite tapawhā

x^{2} - 4 x - 5 = 0

Āhuahanga

4 sin θ cos θ = 2 sin θ

whārite paerangi

y = 3 x + 4

Arithmetic

699 * 533

Poukapa

[2534] [2 - 1 0135]

whārite Simultaneous

{8 x + 2 y = 46 7 x + 3 y = 47

Whakarerekētanga

\frac{d}{d x} \frac{( 3 x ^{2} - 2 )}{( x - 5 )}

Whakaurunga

\int_{0}^{1} x e^{- x^{2}} d x

Ngā Tepe

x \to - 3 lim \frac{x ^{2} - 9}{x ^{2} + 2 x - 3}

Ngā Kaupapa

Ngā Kaupapa

Ngā Ataata

Ngā Raru Ōrite mai i te Rapu Tukutuku

Tohaina

Ngā Tauira