Whakaoti i te x-8div4x^3-15^2-120x-128

$$x-8 \div 4 { x }^{ 3 } - { 15 }^{ 2 } -120x-128$$

Aromātai

$$-2x^{3}-119x-353$$

Ngā Upane Otinga

Whakawehea te 8 ki te 4, kia riro ko 2.

$$x-2x^{3}-15^{2}-120x-128$$

Tātaihia te 15 mā te pū o 2, kia riro ko 225.

$$x-2x^{3}-225-120x-128$$

Pahekotia te x me -120x, ka -119x.

$$-119x-2x^{3}-225-128$$

Tangohia te 128 i te -225, ka -353.

$$-119x-2x^{3}-353$$

Kimi Pārōnaki e ai ki x

$$-6x^{2}-119$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Whakawehea te 8 ki te 4, kia riro ko 2.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x-2x^{3}-15^{2}-120x-128)$$

Tātaihia te 15 mā te pū o 2, kia riro ko 225.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x-2x^{3}-225-120x-128)$$

Pahekotia te x me -120x, ka -119x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-119x-2x^{3}-225-128)$$

Tangohia te 128 i te -225, ka -353.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-119x-2x^{3}-353)$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$-119x^{1-1}+3\left(-2\right)x^{3-1}$$

Tango 1 mai i 1.

$$-119x^{0}+3\left(-2\right)x^{3-1}$$

Whakareatia 3 ki te -2.

$$-119x^{0}-6x^{3-1}$$

Tango 1 mai i 3.

$$-119x^{0}-6x^{2}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$-119-6x^{2}$$