Whakaoti i te x-sqrt{x^2-2x}=0

$$x- \sqrt{ { x }^{ 2 } -2x } =0$$

Whakaoti mō x

$$x=0$$

Ngā Upane Otinga

Me tango x mai i ngā taha e rua o te whārite.

$$-\sqrt{x^{2}-2x}=-x$$

Me whakakore te -1 ki ngā taha e rua.

$$\sqrt{x^{2}-2x}=x$$

Pūruatia ngā taha e rua o te whārite.

$$\left(\sqrt{x^{2}-2x}\right)^{2}=x^{2}$$

Tātaihia te \sqrt{x^{2}-2x} mā te pū o 2, kia riro ko x^{2}-2x.

$$x^{2}-2x=x^{2}$$

Tangohia te x^{2} mai i ngā taha e rua.

$$x^{2}-2x-x^{2}=0$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$-2x=0$$

He ōrite te hua o ngā tau e rua ki 0 ina 0 tētahi o rāua te iti rawa. Tātemea kāore te -2 e ōrite ki 0, me ōrite pū te x ki 0.

$$x=0$$

Whakakapia te 0 mō te x i te whārite x-\sqrt{x^{2}-2x}=0.

$$0-\sqrt{0^{2}-2\times 0}=0$$

Whakarūnātia. Ko te uara x=0 kua ngata te whārite.

$$0=0$$

Ko te whārite \sqrt{x^{2}-2x}=x he rongoā ahurei.

$$x=0$$