Whakaoti i te x=-6-2div(y-3)

$$x=-6-2 \div (y-3)$$

Whakaoti mō y

$$y=\frac{3x+16}{x+6}$$

$$x\neq -6$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe y ki 3 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te y-3.

$$x\left(y-3\right)=\left(y-3\right)\left(-6\right)-2$$

Whakamahia te āhuatanga tohatoha hei whakarea te x ki te y-3.

$$xy-3x=\left(y-3\right)\left(-6\right)-2$$

Whakamahia te āhuatanga tohatoha hei whakarea te y-3 ki te -6.

$$xy-3x=-6y+18-2$$

Tangohia te 2 i te 18, ka 16.

$$xy-3x=-6y+16$$

Me tāpiri te 6y ki ngā taha e rua.

$$xy-3x+6y=16$$

Me tāpiri te 3x ki ngā taha e rua.

$$xy+6y=16+3x$$

Pahekotia ngā kīanga tau katoa e whai ana i te y.

$$\left(x+6\right)y=16+3x$$

He hanga arowhānui tō te whārite.

$$\left(x+6\right)y=3x+16$$

Whakawehea ngā taha e rua ki te x+6.

$$\frac{\left(x+6\right)y}{x+6}=\frac{3x+16}{x+6}$$

Mā te whakawehe ki te x+6 ka wetekia te whakareanga ki te x+6.

$$y=\frac{3x+16}{x+6}$$

Tē taea kia ōrite te tāupe y ki 3.

$$y=\frac{3x+16}{x+6}\text{, }y\neq 3$$

Whakaoti mō x

$$x=-\frac{2\left(3y-8\right)}{y-3}$$

$$y\neq 3$$