Whakaoti i te x=(x+x-x)*xdivx

$$x=(x+x-x) \times x \div x$$

Whakaoti mō x

$$x\neq 0$$

Ngā Upane Otinga

Pahekotia te x me x, ka 2x.

$$x=\frac{\left(2x-x\right)x}{x}$$

Pahekotia te 2x me -x, ka x.

$$x=\frac{xx}{x}$$

Whakareatia te x ki te x, ka x^{2}.

$$x=\frac{x^{2}}{x}$$

Hei whakawehe ngā pū o te pūtake kotahi, tangohia te taupū o te tauraro mai i te taupū o te taurunga. Me tango te 1 i te 2 kia riro ai te 1.

$$x=x^{1}$$

Tātaihia te x mā te pū o 1, kia riro ko x.

$$x=x$$

Tangohia te x mai i ngā taha e rua.

$$x-x=0$$

Pahekotia te x me -x, ka 0.

$$0=0$$

Whakatauritea te 0 me te 0.

$$\text{true}$$

He pono tēnei mō tētahi x ahakoa.

$$x\in \mathrm{R}$$