Whakaoti i te x=sqrt{2+x+y}

$$x= \sqrt{ 2+x+y }$$

Whakaoti mō y

$$y=\left(x-2\right)\left(x+1\right)$$

$$x\geq 0$$

Ngā Upane mō te Whakaoti Whārite Pūtake

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$\sqrt{2+x+y}=x$$

Pūruatia ngā taha e rua o te whārite.

$$y+x+2=x^{2}$$

Me tango 2+x mai i ngā taha e rua o te whārite.

$$y+x+2-\left(x+2\right)=x^{2}-\left(x+2\right)$$

Mā te tango i te 2+x i a ia ake anō ka toe ko te 0.

$$y=x^{2}-\left(x+2\right)$$

Tango 2+x mai i x^{2}.

$$y=\left(x-2\right)\left(x+1\right)$$

Whakaoti mō x (complex solution)

$$\left\{\begin{matrix}x=\frac{-\sqrt{4y+9}+1}{2}\text{, }&arg(\frac{-\sqrt{4y+9}+1}{2})<\pi \text{ or }y=-2\\x=\frac{\sqrt{4y+9}+1}{2}\text{, }&arg(\frac{\sqrt{4y+9}+1}{2})<\pi \end{matrix}\right.$$

Whakaoti mō y (complex solution)

$$y=\left(x-2\right)\left(x+1\right)$$

$$arg(x)<\pi \text{ or }x=0$$

Whakaoti mō x

$$\left\{\begin{matrix}x=\frac{\sqrt{4y+9}+1}{2}\text{, }&y\geq -\frac{9}{4}\\x=\frac{-\sqrt{4y+9}+1}{2}\text{, }&y\geq -\frac{9}{4}\text{ and }y\leq -2\end{matrix}\right.$$