Whakaoti i te x=sqrt{2x^2}

$$x= \sqrt{ 2 { x }^{ 2 } }$$

Whakaoti mō x

$$x=0$$

Ngā Upane Otinga

Pūruatia ngā taha e rua o te whārite.

$$x^{2}=\left(\sqrt{2x^{2}}\right)^{2}$$

Tātaihia te \sqrt{2x^{2}} mā te pū o 2, kia riro ko 2x^{2}.

$$x^{2}=2x^{2}$$

Tangohia te 2x^{2} mai i ngā taha e rua.

$$x^{2}-2x^{2}=0$$

Pahekotia te x^{2} me -2x^{2}, ka -x^{2}.

$$-x^{2}=0$$

Whakawehea ngā taha e rua ki te -1. Ko te kore i whakawehea ki te tau ehara te kore ka hua ko te kore.

$$x^{2}=0$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=0 x=0$$

Kua oti te whārite te whakatau. He ōrite ngā whakatau.

$$x=0$$

Whakakapia te 0 mō te x i te whārite x=\sqrt{2x^{2}}.

$$0=\sqrt{2\times 0^{2}}$$

Whakarūnātia. Ko te uara x=0 kua ngata te whārite.

$$0=0$$

Ko te whārite x=\sqrt{2x^{2}} he rongoā ahurei.

$$x=0$$