Whakaoti i te x=6x-15/x-2

$$x= \frac{ 6x-15 }{ x-2 }$$

Whakaoti mō x

$$x=3$$

$$x=5$$

Ngā Upane Whakamahi Tauwehe

Tangohia te \frac{6x-15}{x-2} mai i ngā taha e rua.

$$x-\frac{6x-15}{x-2}=0$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia x ki te \frac{x-2}{x-2}.

$$\frac{x\left(x-2\right)}{x-2}-\frac{6x-15}{x-2}=0$$

Tā te mea he rite te tauraro o \frac{x\left(x-2\right)}{x-2} me \frac{6x-15}{x-2}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{x\left(x-2\right)-\left(6x-15\right)}{x-2}=0$$

Mahia ngā whakarea i roto o x\left(x-2\right)-\left(6x-15\right).

$$\frac{x^{2}-2x-6x+15}{x-2}=0$$

Whakakotahitia ngā kupu rite i x^{2}-2x-6x+15.

$$\frac{x^{2}-8x+15}{x-2}=0$$

Tē taea kia ōrite te tāupe x ki 2 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te x-2.

$$x^{2}-8x+15=0$$

Hei whakaoti i te whārite, whakatauwehea te x^{2}-8x+15 mā te whakamahi i te tātai x^{2}+\left(a+b\right)x+ab=\left(x+a\right)\left(x+b\right). Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.

$$a+b=-8 ab=15$$

I te mea kua tōrunga te ab, he ōrite te tohu o a me b. I te mea kua tōraro te a+b, he tōraro hoki a a me b. Whakarārangitia ngā tau tōpū takirua pērā katoa ka hoatu i te hua 15.

$$-1,-15 -3,-5$$

Tātaihia te tapeke mō ia takirua.

$$-1-15=-16 -3-5=-8$$

Ko te otinga te takirua ka hoatu i te tapeke -8.

$$a=-5 b=-3$$

Me tuhi anō te kīanga whakatauwehe \left(x+a\right)\left(x+b\right) mā ngā uara i tātaihia.

$$\left(x-5\right)\left(x-3\right)$$

Hei kimi otinga whārite, me whakaoti te x-5=0 me te x-3=0.

$$x=5 x=3$$

Ngā Upane Whakamahi Tauwehe Mā te Whakarōpū

Tangohia te \frac{6x-15}{x-2} mai i ngā taha e rua.

$$x-\frac{6x-15}{x-2}=0$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia x ki te \frac{x-2}{x-2}.

$$\frac{x\left(x-2\right)}{x-2}-\frac{6x-15}{x-2}=0$$

Tā te mea he rite te tauraro o \frac{x\left(x-2\right)}{x-2} me \frac{6x-15}{x-2}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{x\left(x-2\right)-\left(6x-15\right)}{x-2}=0$$

Mahia ngā whakarea i roto o x\left(x-2\right)-\left(6x-15\right).

$$\frac{x^{2}-2x-6x+15}{x-2}=0$$

Whakakotahitia ngā kupu rite i x^{2}-2x-6x+15.

$$\frac{x^{2}-8x+15}{x-2}=0$$

Tē taea kia ōrite te tāupe x ki 2 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te x-2.

$$x^{2}-8x+15=0$$

Hei whakaoti i te whārite, whakatauwehea te taha mauī mā te whakarōpū. Tuatahi, me tuhi anō te taha mauī hei x^{2}+ax+bx+15. Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.

$$a+b=-8 ab=1\times 15=15$$

I te mea kua tōrunga te ab, he ōrite te tohu o a me b. I te mea kua tōraro te a+b, he tōraro hoki a a me b. Whakarārangitia ngā tau tōpū takirua pērā katoa ka hoatu i te hua 15.

$$-1,-15 -3,-5$$

Tātaihia te tapeke mō ia takirua.

$$-1-15=-16 -3-5=-8$$

Ko te otinga te takirua ka hoatu i te tapeke -8.

$$a=-5 b=-3$$

Tuhia anō te x^{2}-8x+15 hei \left(x^{2}-5x\right)+\left(-3x+15\right).

$$\left(x^{2}-5x\right)+\left(-3x+15\right)$$

Tauwehea te x i te tuatahi me te -3 i te rōpū tuarua.

$$x\left(x-5\right)-3\left(x-5\right)$$

Whakatauwehea atu te kīanga pātahi x-5 mā te whakamahi i te āhuatanga tātai tohatoha.

$$\left(x-5\right)\left(x-3\right)$$

Hei kimi otinga whārite, me whakaoti te x-5=0 me te x-3=0.

$$x=5 x=3$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te \frac{6x-15}{x-2} mai i ngā taha e rua.

$$x-\frac{6x-15}{x-2}=0$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia x ki te \frac{x-2}{x-2}.

$$\frac{x\left(x-2\right)}{x-2}-\frac{6x-15}{x-2}=0$$

Tā te mea he rite te tauraro o \frac{x\left(x-2\right)}{x-2} me \frac{6x-15}{x-2}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{x\left(x-2\right)-\left(6x-15\right)}{x-2}=0$$

Mahia ngā whakarea i roto o x\left(x-2\right)-\left(6x-15\right).

$$\frac{x^{2}-2x-6x+15}{x-2}=0$$

Whakakotahitia ngā kupu rite i x^{2}-2x-6x+15.

$$\frac{x^{2}-8x+15}{x-2}=0$$

Tē taea kia ōrite te tāupe x ki 2 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te x-2.

$$x^{2}-8x+15=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, -8 mō b, me 15 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-\left(-8\right)±\sqrt{\left(-8\right)^{2}-4\times 15}}{2}$$

Pūrua -8.

$$x=\frac{-\left(-8\right)±\sqrt{64-4\times 15}}{2}$$

Whakareatia -4 ki te 15.

$$x=\frac{-\left(-8\right)±\sqrt{64-60}}{2}$$

Tāpiri 64 ki te -60.

$$x=\frac{-\left(-8\right)±\sqrt{4}}{2}$$

Tuhia te pūtakerua o te 4.

$$x=\frac{-\left(-8\right)±2}{2}$$

Ko te tauaro o -8 ko 8.

$$x=\frac{8±2}{2}$$

Nā, me whakaoti te whārite x=\frac{8±2}{2} ina he tāpiri te ±. Tāpiri 8 ki te 2.

$$x=\frac{10}{2}$$

Whakawehe 10 ki te 2.

$$x=5$$

Nā, me whakaoti te whārite x=\frac{8±2}{2} ina he tango te ±. Tango 2 mai i 8.

$$x=\frac{6}{2}$$

Whakawehe 6 ki te 2.

$$x=3$$

Kua oti te whārite te whakatau.

$$x=5 x=3$$

Ngā Upane mō te Whakaoti i te Pūrua

Tangohia te \frac{6x-15}{x-2} mai i ngā taha e rua.

$$x-\frac{6x-15}{x-2}=0$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia x ki te \frac{x-2}{x-2}.

$$\frac{x\left(x-2\right)}{x-2}-\frac{6x-15}{x-2}=0$$

Tā te mea he rite te tauraro o \frac{x\left(x-2\right)}{x-2} me \frac{6x-15}{x-2}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{x\left(x-2\right)-\left(6x-15\right)}{x-2}=0$$

Mahia ngā whakarea i roto o x\left(x-2\right)-\left(6x-15\right).

$$\frac{x^{2}-2x-6x+15}{x-2}=0$$

Whakakotahitia ngā kupu rite i x^{2}-2x-6x+15.

$$\frac{x^{2}-8x+15}{x-2}=0$$

Tē taea kia ōrite te tāupe x ki 2 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te x-2.

$$x^{2}-8x+15=0$$

Tangohia te 15 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$x^{2}-8x=-15$$

Whakawehea te -8, te tau whakarea o te kīanga tau x, ki te 2 kia riro ai te -4. Nā, tāpiria te pūrua o te -4 ki ngā taha e rua o te whārite. Mā konei e pūrua tika tonu ai te taha mauī o te whārite.

$$x^{2}-8x+\left(-4\right)^{2}=-15+\left(-4\right)^{2}$$

Pūrua -4.

$$x^{2}-8x+16=-15+16$$

Tāpiri -15 ki te 16.

$$x^{2}-8x+16=1$$

Tauwehea te x^{2}-8x+16. Ko te tikanga, ina ko x^{2}+bx+c he pūrua tika, ka taea te tauwehe i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-4\right)^{2}=1$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$\sqrt{\left(x-4\right)^{2}}=\sqrt{1}$$

Whakarūnātia.

$$x-4=1 x-4=-1$$

Me tāpiri 4 ki ngā taha e rua o te whārite.

$$x=5 x=3$$