Whakaoti i te x=-8y/-12y-6

$$x= \frac{ -8y }{ -12y-6 }$$

Whakaoti mō y

$$y=\frac{3x}{2\left(2-3x\right)}$$

$$x\neq \frac{2}{3}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe y ki -\frac{1}{2} nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te 6\left(-2y-1\right).

$$x\times 6\left(-2y-1\right)=-8y$$

Whakamahia te āhuatanga tohatoha hei whakarea te x\times 6 ki te -2y-1.

$$-12xy-x\times 6=-8y$$

Whakareatia te -1 ki te 6, ka -6.

$$-12xy-6x=-8y$$

Me tāpiri te 8y ki ngā taha e rua.

$$-12xy-6x+8y=0$$

Me tāpiri te 6x ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$-12xy+8y=6x$$

Pahekotia ngā kīanga tau katoa e whai ana i te y.

$$\left(-12x+8\right)y=6x$$

He hanga arowhānui tō te whārite.

$$\left(8-12x\right)y=6x$$

Whakawehea ngā taha e rua ki te -12x+8.

$$\frac{\left(8-12x\right)y}{8-12x}=\frac{6x}{8-12x}$$

Mā te whakawehe ki te -12x+8 ka wetekia te whakareanga ki te -12x+8.

$$y=\frac{6x}{8-12x}$$

Whakawehe 6x ki te -12x+8.

$$y=\frac{3x}{2\left(2-3x\right)}$$

Tē taea kia ōrite te tāupe y ki -\frac{1}{2}.

$$y=\frac{3x}{2\left(2-3x\right)}\text{, }y\neq -\frac{1}{2}$$

Whakaoti mō x

$$x=\frac{4y}{3\left(2y+1\right)}$$

$$y\neq -\frac{1}{2}$$