Whakaoti i te x+7x-1-3left(x-2right)=-5+x

$$x+7x-1-3 \left( x-2 \right) = -5+x$$

Whakaoti mō x

$$x = -\frac{5}{2} = -2\frac{1}{2} = -2.5$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Pahekotia te x me 7x, ka 8x.

$$8x-1-3\left(x-2\right)=-5+x$$

Whakamahia te āhuatanga tohatoha hei whakarea te -3 ki te x-2.

$$8x-1-3x+6=-5+x$$

Pahekotia te 8x me -3x, ka 5x.

$$5x-1+6=-5+x$$

Tāpirihia te -1 ki te 6, ka 5.

$$5x+5=-5+x$$

Tangohia te x mai i ngā taha e rua.

$$5x+5-x=-5$$

Pahekotia te 5x me -x, ka 4x.

$$4x+5=-5$$

Tangohia te 5 mai i ngā taha e rua.

$$4x=-5-5$$

Tangohia te 5 i te -5, ka -10.

$$4x=-10$$

Whakawehea ngā taha e rua ki te 4.

$$x=\frac{-10}{4}$$

Whakahekea te hautanga \frac{-10}{4} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$x=-\frac{5}{2}$$