Whakaoti mō x
x=\frac{5}{e^{y}-2}
y\neq \ln(2)
Whakaoti mō y
y=\ln(2+\frac{5}{x})
x>0\text{ or }x<-\frac{5}{2}
Graph
Tohaina
Kua tāruatia ki te papatopenga
\left(e^{y}-2\right)x=5
Pahekotia ngā kīanga tau katoa e whai ana i te x.
\frac{\left(e^{y}-2\right)x}{e^{y}-2}=\frac{5}{e^{y}-2}
Whakawehea ngā taha e rua ki te e^{y}-2.
x=\frac{5}{e^{y}-2}
Mā te whakawehe ki te e^{y}-2 ka wetekia te whakareanga ki te e^{y}-2.
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