Whakaoti i te x-12leq3(x-2)+x

$$x - 12 \leq 3 ( x - 2 ) + x$$

Whakaoti mō x

$$x\geq -2$$

Ngā Upane Otinga

Whakamahia te āhuatanga tohatoha hei whakarea te 3 ki te x-2.

$$x-12\leq 3x-6+x$$

Pahekotia te 3x me x, ka 4x.

$$x-12\leq 4x-6$$

Tangohia te 4x mai i ngā taha e rua.

$$x-12-4x\leq -6$$

Pahekotia te x me -4x, ka -3x.

$$-3x-12\leq -6$$

Me tāpiri te 12 ki ngā taha e rua.

$$-3x\leq -6+12$$

Tāpirihia te -6 ki te 12, ka 6.

$$-3x\leq 6$$

Whakawehea ngā taha e rua ki te -3. I te mea he tōraro a -3, ka huri te ahunga koreōrite.

$$x\geq \frac{6}{-3}$$

Whakawehea te 6 ki te -3, kia riro ko -2.

$$x\geq -2$$