Whakaoti i te x-1/x+2=9/1

$$x - 1 / x + 2 = 9 / 1$$

Whakaoti mō x

$$x = \frac{\sqrt{53} + 7}{2} \approx 7.140054945$$

$$x=\frac{7-\sqrt{53}}{2}\approx -0.140054945$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tē taea kia ōrite te tāupe x ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te x.

$$xx-1+x\times 2=x\times 9$$

Whakareatia te x ki te x, ka x^{2}.

$$x^{2}-1+x\times 2=x\times 9$$

Tangohia te x\times 9 mai i ngā taha e rua.

$$x^{2}-1+x\times 2-x\times 9=0$$

Pahekotia te x\times 2 me -x\times 9, ka -7x.

$$x^{2}-1-7x=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$x^{2}-7x-1=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, -7 mō b, me -1 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-\left(-7\right)±\sqrt{\left(-7\right)^{2}-4\left(-1\right)}}{2}$$

Pūrua -7.

$$x=\frac{-\left(-7\right)±\sqrt{49-4\left(-1\right)}}{2}$$

Whakareatia -4 ki te -1.

$$x=\frac{-\left(-7\right)±\sqrt{49+4}}{2}$$

Tāpiri 49 ki te 4.

$$x=\frac{-\left(-7\right)±\sqrt{53}}{2}$$

Ko te tauaro o -7 ko 7.

$$x=\frac{7±\sqrt{53}}{2}$$

Nā, me whakaoti te whārite x=\frac{7±\sqrt{53}}{2} ina he tāpiri te ±. Tāpiri 7 ki te \sqrt{53}.

$$x=\frac{\sqrt{53}+7}{2}$$

Nā, me whakaoti te whārite x=\frac{7±\sqrt{53}}{2} ina he tango te ±. Tango \sqrt{53} mai i 7.

$$x=\frac{7-\sqrt{53}}{2}$$

Kua oti te whārite te whakatau.

$$x=\frac{\sqrt{53}+7}{2} x=\frac{7-\sqrt{53}}{2}$$

Ngā Upane mō te Whakaoti i te Pūrua

Tē taea kia ōrite te tāupe x ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te x.

$$xx-1+x\times 2=x\times 9$$

Whakareatia te x ki te x, ka x^{2}.

$$x^{2}-1+x\times 2=x\times 9$$

Tangohia te x\times 9 mai i ngā taha e rua.

$$x^{2}-1+x\times 2-x\times 9=0$$

Pahekotia te x\times 2 me -x\times 9, ka -7x.

$$x^{2}-1-7x=0$$

Me tāpiri te 1 ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$x^{2}-7x=1$$

Whakawehea te -7, te tau whakarea o te kīanga tau x, ki te 2 kia riro ai te -\frac{7}{2}. Nā, tāpiria te pūrua o te -\frac{7}{2} ki ngā taha e rua o te whārite. Mā konei e pūrua tika tonu ai te taha mauī o te whārite.

$$x^{2}-7x+\left(-\frac{7}{2}\right)^{2}=1+\left(-\frac{7}{2}\right)^{2}$$

Pūruatia -\frac{7}{2} mā te pūrua i te taurunga me te tauraro o te hautanga.

$$x^{2}-7x+\frac{49}{4}=1+\frac{49}{4}$$

Tāpiri 1 ki te \frac{49}{4}.

$$x^{2}-7x+\frac{49}{4}=\frac{53}{4}$$

Tauwehea x^{2}-7x+\frac{49}{4}. Ko te tikanga pūnoa, ina ko x^{2}+bx+c he pūrua tika pūrua tika pū, ka taea taua mea te tauwehea i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-\frac{7}{2}\right)^{2}=\frac{53}{4}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$\sqrt{\left(x-\frac{7}{2}\right)^{2}}=\sqrt{\frac{53}{4}}$$

Whakarūnātia.

$$x-\frac{7}{2}=\frac{\sqrt{53}}{2} x-\frac{7}{2}=-\frac{\sqrt{53}}{2}$$

Me tāpiri \frac{7}{2} ki ngā taha e rua o te whārite.

$$x=\frac{\sqrt{53}+7}{2} x=\frac{7-\sqrt{53}}{2}$$