Whakaoti i te x-u-1/3=u-1-u/2

$$x - \frac { u - 1 } { 3 } = u - \frac { 1 - u } { 2 }$$

Whakaoti mō u

$$u=\frac{6x+5}{11}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakarea ngā taha e rua o te whārite ki te 6, arā, te tauraro pātahi he tino iti rawa te kitea o 3,2.

$$6x-2\left(u-1\right)=6u-3\left(1-u\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -2 ki te u-1.

$$6x-2u+2=6u-3\left(1-u\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -3 ki te 1-u.

$$6x-2u+2=6u-3+3u$$

Pahekotia te 6u me 3u, ka 9u.

$$6x-2u+2=9u-3$$

Tangohia te 9u mai i ngā taha e rua.

$$6x-2u+2-9u=-3$$

Pahekotia te -2u me -9u, ka -11u.

$$6x-11u+2=-3$$

Tangohia te 6x mai i ngā taha e rua.

$$-11u+2=-3-6x$$

Tangohia te 2 mai i ngā taha e rua.

$$-11u=-3-6x-2$$

Tangohia te 2 i te -3, ka -5.

$$-11u=-5-6x$$

He hanga arowhānui tō te whārite.

$$-11u=-6x-5$$

Whakawehea ngā taha e rua ki te -11.

$$\frac{-11u}{-11}=\frac{-6x-5}{-11}$$

Mā te whakawehe ki te -11 ka wetekia te whakareanga ki te -11.

$$u=\frac{-6x-5}{-11}$$

Whakawehe -5-6x ki te -11.

$$u=\frac{6x+5}{11}$$

Whakaoti mō x

$$x=\frac{11u-5}{6}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakarea ngā taha e rua o te whārite ki te 6, arā, te tauraro pātahi he tino iti rawa te kitea o 3,2.

$$6x-2\left(u-1\right)=6u-3\left(1-u\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -2 ki te u-1.

$$6x-2u+2=6u-3\left(1-u\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -3 ki te 1-u.

$$6x-2u+2=6u-3+3u$$

Pahekotia te 6u me 3u, ka 9u.

$$6x-2u+2=9u-3$$

Me tāpiri te 2u ki ngā taha e rua.

$$6x+2=9u-3+2u$$

Pahekotia te 9u me 2u, ka 11u.

$$6x+2=11u-3$$

Tangohia te 2 mai i ngā taha e rua.

$$6x=11u-3-2$$

Tangohia te 2 i te -3, ka -5.

$$6x=11u-5$$

Whakawehea ngā taha e rua ki te 6.

$$\frac{6x}{6}=\frac{11u-5}{6}$$

Mā te whakawehe ki te 6 ka wetekia te whakareanga ki te 6.

$$x=\frac{11u-5}{6}$$