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Kimi Pārōnaki e ai ki x
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\frac{\mathrm{d}}{\mathrm{d}x}(\frac{1}{5}x)
Pahekotia te x me -\frac{4}{5}x, ka \frac{1}{5}x.
\frac{1}{5}x^{1-1}
Ko te pārōnaki o ax^{n} ko nax^{n-1}.
\frac{1}{5}x^{0}
Tango 1 mai i 1.
\frac{1}{5}\times 1
Mō tētahi kupu t mahue te 0, t^{0}=1.
\frac{1}{5}
Mō tētahi kupu t, t\times 1=t me 1t=t.
\frac{1}{5}x
Pahekotia te x me -\frac{4}{5}x, ka \frac{1}{5}x.