Whakaoti i te x-3/5x+1-2/3x=7/5-1/3x

$$x - \frac { 3 } { 5 } x + 1 - \frac { 2 } { 3 } x = \frac { 7 } { 5 } - \frac { 1 } { 3 } x$$

Whakaoti mō x

$$x=6$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Pahekotia te x me -\frac{3}{5}x, ka \frac{2}{5}x.

$$\frac{2}{5}x+1-\frac{2}{3}x=\frac{7}{5}-\frac{1}{3}x$$

Pahekotia te \frac{2}{5}x me -\frac{2}{3}x, ka -\frac{4}{15}x.

$$-\frac{4}{15}x+1=\frac{7}{5}-\frac{1}{3}x$$

Me tāpiri te \frac{1}{3}x ki ngā taha e rua.

$$-\frac{4}{15}x+1+\frac{1}{3}x=\frac{7}{5}$$

Pahekotia te -\frac{4}{15}x me \frac{1}{3}x, ka \frac{1}{15}x.

$$\frac{1}{15}x+1=\frac{7}{5}$$

Tangohia te 1 mai i ngā taha e rua.

$$\frac{1}{15}x=\frac{7}{5}-1$$

Me tahuri te 1 ki te hautau \frac{5}{5}.

$$\frac{1}{15}x=\frac{7}{5}-\frac{5}{5}$$

Tā te mea he rite te tauraro o \frac{7}{5} me \frac{5}{5}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{1}{15}x=\frac{7-5}{5}$$

Tangohia te 5 i te 7, ka 2.

$$\frac{1}{15}x=\frac{2}{5}$$

Me whakarea ngā taha e rua ki te 15, te tau utu o \frac{1}{15}.

$$x=\frac{2}{5}\times 15$$

Tuhia te \frac{2}{5}\times 15 hei hautanga kotahi.

$$x=\frac{2\times 15}{5}$$

Whakareatia te 2 ki te 15, ka 30.

$$x=\frac{30}{5}$$

Whakawehea te 30 ki te 5, kia riro ko 6.

$$x=6$$