Whakaoti i te x(x-5)+2(x-1)=(x+1)^2

$$x ( x - 5 ) + 2 ( x - 1 ) = ( x + 1 ) ^ { 2 }$$

Whakaoti mō x

$$x=-\frac{3}{5}=-0.6$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te x ki te x-5.

$$x^{2}-5x+2\left(x-1\right)=\left(x+1\right)^{2}$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te x-1.

$$x^{2}-5x+2x-2=\left(x+1\right)^{2}$$

Pahekotia te -5x me 2x, ka -3x.

$$x^{2}-3x-2=\left(x+1\right)^{2}$$

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(x+1\right)^{2}.

$$x^{2}-3x-2=x^{2}+2x+1$$

Tangohia te x^{2} mai i ngā taha e rua.

$$x^{2}-3x-2-x^{2}=2x+1$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$-3x-2=2x+1$$

Tangohia te 2x mai i ngā taha e rua.

$$-3x-2-2x=1$$

Pahekotia te -3x me -2x, ka -5x.

$$-5x-2=1$$

Me tāpiri te 2 ki ngā taha e rua.

$$-5x=1+2$$

Tāpirihia te 1 ki te 2, ka 3.

$$-5x=3$$

Whakawehea ngā taha e rua ki te -5.

$$x=\frac{3}{-5}$$

Ka taea te hautanga \frac{3}{-5} te tuhi anō ko -\frac{3}{5} mā te tango i te tohu tōraro.

$$x=-\frac{3}{5}$$