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x^{2}-5x+2\left(x-1\right)=x+1
Whakamahia te āhuatanga tohatoha hei whakarea te x ki te x-5.
x^{2}-5x+2x-2=x+1
Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te x-1.
x^{2}-3x-2=x+1
Pahekotia te -5x me 2x, ka -3x.
x^{2}-3x-2-x=1
Tangohia te x mai i ngā taha e rua.
x^{2}-4x-2=1
Pahekotia te -3x me -x, ka -4x.
x^{2}-4x-2-1=0
Tangohia te 1 mai i ngā taha e rua.
x^{2}-4x-3=0
Tangohia te 1 i te -2, ka -3.
x=\frac{-\left(-4\right)±\sqrt{\left(-4\right)^{2}-4\left(-3\right)}}{2}
Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, -4 mō b, me -3 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-4\right)±\sqrt{16-4\left(-3\right)}}{2}
Pūrua -4.
x=\frac{-\left(-4\right)±\sqrt{16+12}}{2}
Whakareatia -4 ki te -3.
x=\frac{-\left(-4\right)±\sqrt{28}}{2}
Tāpiri 16 ki te 12.
x=\frac{-\left(-4\right)±2\sqrt{7}}{2}
Tuhia te pūtakerua o te 28.
x=\frac{4±2\sqrt{7}}{2}
Ko te tauaro o -4 ko 4.
x=\frac{2\sqrt{7}+4}{2}
Nā, me whakaoti te whārite x=\frac{4±2\sqrt{7}}{2} ina he tāpiri te ±. Tāpiri 4 ki te 2\sqrt{7}.
x=\sqrt{7}+2
Whakawehe 4+2\sqrt{7} ki te 2.
x=\frac{4-2\sqrt{7}}{2}
Nā, me whakaoti te whārite x=\frac{4±2\sqrt{7}}{2} ina he tango te ±. Tango 2\sqrt{7} mai i 4.
x=2-\sqrt{7}
Whakawehe 4-2\sqrt{7} ki te 2.
x=\sqrt{7}+2 x=2-\sqrt{7}
Kua oti te whārite te whakatau.
x^{2}-5x+2\left(x-1\right)=x+1
Whakamahia te āhuatanga tohatoha hei whakarea te x ki te x-5.
x^{2}-5x+2x-2=x+1
Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te x-1.
x^{2}-3x-2=x+1
Pahekotia te -5x me 2x, ka -3x.
x^{2}-3x-2-x=1
Tangohia te x mai i ngā taha e rua.
x^{2}-4x-2=1
Pahekotia te -3x me -x, ka -4x.
x^{2}-4x=1+2
Me tāpiri te 2 ki ngā taha e rua.
x^{2}-4x=3
Tāpirihia te 1 ki te 2, ka 3.
x^{2}-4x+\left(-2\right)^{2}=3+\left(-2\right)^{2}
Whakawehea te -4, te tau whakarea o te kīanga tau x, ki te 2 kia riro ai te -2. Nā, tāpiria te pūrua o te -2 ki ngā taha e rua o te whārite. Mā konei e pūrua tika tonu ai te taha mauī o te whārite.
x^{2}-4x+4=3+4
Pūrua -2.
x^{2}-4x+4=7
Tāpiri 3 ki te 4.
\left(x-2\right)^{2}=7
Tauwehea te x^{2}-4x+4. Ko te tikanga, ina ko x^{2}+bx+c he pūrua tika, ka taea te tauwehe i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-2\right)^{2}}=\sqrt{7}
Tuhia te pūtakerua o ngā taha e rua o te whārite.
x-2=\sqrt{7} x-2=-\sqrt{7}
Whakarūnātia.
x=\sqrt{7}+2 x=2-\sqrt{7}
Me tāpiri 2 ki ngā taha e rua o te whārite.