Whakaoti i te x(x-1)-(x-1/3)(x+1/3)

$$x ( x - 1 ) - ( x - \frac { 1 } { 3 } ) ( x + \frac { 1 } { 3 } )$$

Aromātai

$$\frac{1}{9}-x$$

Ngā Upane Otinga

Whakamahia te āhuatanga tohatoha hei whakarea te x ki te x-1.

$$x^{2}-x-\left(x-\frac{1}{3}\right)\left(x+\frac{1}{3}\right)$$

Whakaarohia te \left(x-\frac{1}{3}\right)\left(x+\frac{1}{3}\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$x^{2}-x-\left(x^{2}-\left(\frac{1}{3}\right)^{2}\right)$$

Tātaihia te \frac{1}{3} mā te pū o 2, kia riro ko \frac{1}{9}.

$$x^{2}-x-\left(x^{2}-\frac{1}{9}\right)$$

Hei kimi i te tauaro o x^{2}-\frac{1}{9}, kimihia te tauaro o ia taurangi.

$$x^{2}-x-x^{2}-\left(-\frac{1}{9}\right)$$

Ko te tauaro o -\frac{1}{9} ko \frac{1}{9}.

$$x^{2}-x-x^{2}+\frac{1}{9}$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$-x+\frac{1}{9}$$

Whakaroha

$$\frac{1}{9}-x$$

Ngā Upane Otinga

Whakamahia te āhuatanga tohatoha hei whakarea te x ki te x-1.

$$x^{2}-x-\left(x-\frac{1}{3}\right)\left(x+\frac{1}{3}\right)$$

Whakaarohia te \left(x-\frac{1}{3}\right)\left(x+\frac{1}{3}\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$x^{2}-x-\left(x^{2}-\left(\frac{1}{3}\right)^{2}\right)$$

Tātaihia te \frac{1}{3} mā te pū o 2, kia riro ko \frac{1}{9}.

$$x^{2}-x-\left(x^{2}-\frac{1}{9}\right)$$

Hei kimi i te tauaro o x^{2}-\frac{1}{9}, kimihia te tauaro o ia taurangi.

$$x^{2}-x-x^{2}-\left(-\frac{1}{9}\right)$$

Ko te tauaro o -\frac{1}{9} ko \frac{1}{9}.

$$x^{2}-x-x^{2}+\frac{1}{9}$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$-x+\frac{1}{9}$$