Whakaoti i te x(x+4)-3=4(x+19.5)

$$x ( x + 4 ) - 3 = 4 ( x + 19.5 )$$

Whakaoti mō x

$$x=-9$$

$$x=9$$

Ngā Upane mā te Kimi Pūtakerua

Whakamahia te āhuatanga tohatoha hei whakarea te x ki te x+4.

$$x^{2}+4x-3=4\left(x+19.5\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 4 ki te x+19.5.

$$x^{2}+4x-3=4x+78$$

Tangohia te 4x mai i ngā taha e rua.

$$x^{2}+4x-3-4x=78$$

Pahekotia te 4x me -4x, ka 0.

$$x^{2}-3=78$$

Me tāpiri te 3 ki ngā taha e rua.

$$x^{2}=78+3$$

Tāpirihia te 78 ki te 3, ka 81.

$$x^{2}=81$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=9 x=-9$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakamahia te āhuatanga tohatoha hei whakarea te x ki te x+4.

$$x^{2}+4x-3=4\left(x+19.5\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 4 ki te x+19.5.

$$x^{2}+4x-3=4x+78$$

Tangohia te 4x mai i ngā taha e rua.

$$x^{2}+4x-3-4x=78$$

Pahekotia te 4x me -4x, ka 0.

$$x^{2}-3=78$$

Tangohia te 78 mai i ngā taha e rua.

$$x^{2}-3-78=0$$

Tangohia te 78 i te -3, ka -81.

$$x^{2}-81=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -81 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-81\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-81\right)}}{2}$$

Whakareatia -4 ki te -81.

$$x=\frac{0±\sqrt{324}}{2}$$

Tuhia te pūtakerua o te 324.

$$x=\frac{0±18}{2}$$

Nā, me whakaoti te whārite x=\frac{0±18}{2} ina he tāpiri te ±. Whakawehe 18 ki te 2.

$$x=9$$

Nā, me whakaoti te whārite x=\frac{0±18}{2} ina he tango te ±. Whakawehe -18 ki te 2.

$$x=-9$$

Kua oti te whārite te whakatau.

$$x=9 x=-9$$