Whakaoti i te x(600-500m)+124+40m+500=12000

$$x ( 600 - 500 m ) + 124 + 40 m + 500 = 12000$$

Whakaoti mō m

$$m=-\frac{6\left(25x-474\right)}{5\left(2-25x\right)}$$

$$x\neq \frac{2}{25}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te x ki te 600-500m.

$$600x-500xm+124+40m+500=12000$$

Tāpirihia te 124 ki te 500, ka 624.

$$600x-500xm+624+40m=12000$$

Tangohia te 600x mai i ngā taha e rua.

$$-500xm+624+40m=12000-600x$$

Tangohia te 624 mai i ngā taha e rua.

$$-500xm+40m=12000-600x-624$$

Tangohia te 624 i te 12000, ka 11376.

$$-500xm+40m=11376-600x$$

Pahekotia ngā kīanga tau katoa e whai ana i te m.

$$\left(-500x+40\right)m=11376-600x$$

He hanga arowhānui tō te whārite.

$$\left(40-500x\right)m=11376-600x$$

Whakawehea ngā taha e rua ki te -500x+40.

$$\frac{\left(40-500x\right)m}{40-500x}=\frac{11376-600x}{40-500x}$$

Mā te whakawehe ki te -500x+40 ka wetekia te whakareanga ki te -500x+40.

$$m=\frac{11376-600x}{40-500x}$$

Whakawehe 11376-600x ki te -500x+40.

$$m=\frac{6\left(474-25x\right)}{5\left(2-25x\right)}$$

Whakaoti mō x

$$x=-\frac{2\left(5m-1422\right)}{25\left(6-5m\right)}$$

$$m\neq \frac{6}{5}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te x ki te 600-500m.

$$600x-500xm+124+40m+500=12000$$

Tāpirihia te 124 ki te 500, ka 624.

$$600x-500xm+624+40m=12000$$

Tangohia te 624 mai i ngā taha e rua.

$$600x-500xm+40m=12000-624$$

Tangohia te 624 i te 12000, ka 11376.

$$600x-500xm+40m=11376$$

Tangohia te 40m mai i ngā taha e rua.

$$600x-500xm=11376-40m$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(600-500m\right)x=11376-40m$$

Whakawehea ngā taha e rua ki te 600-500m.

$$\frac{\left(600-500m\right)x}{600-500m}=\frac{11376-40m}{600-500m}$$

Mā te whakawehe ki te 600-500m ka wetekia te whakareanga ki te 600-500m.

$$x=\frac{11376-40m}{600-500m}$$

Whakawehe 11376-40m ki te 600-500m.

$$x=\frac{2\left(1422-5m\right)}{25\left(6-5m\right)}$$