Whakaoti i te x(4-5i)+y(2+6i)=-12-7i

$$x ( 4 - 5 i ) + y ( 2 + 6 i ) = - 12 - 7 i$$

Whakaoti mō x

$$x=\left(\frac{22}{41}-\frac{34}{41}i\right)y+\left(-\frac{13}{41}-\frac{88}{41}i\right)$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te y\left(2+6i\right) mai i ngā taha e rua.

$$x\left(4-5i\right)=-12-7i-y\left(2+6i\right)$$

Whakareatia te -1 ki te 2+6i, ka -2-6i.

$$x\left(4-5i\right)=-12-7i+\left(-2-6i\right)y$$

He hanga arowhānui tō te whārite.

$$\left(4-5i\right)x=\left(-2-6i\right)y+\left(-12-7i\right)$$

Whakawehea ngā taha e rua ki te 4-5i.

$$\frac{\left(4-5i\right)x}{4-5i}=\frac{\left(-2-6i\right)y+\left(-12-7i\right)}{4-5i}$$

Mā te whakawehe ki te 4-5i ka wetekia te whakareanga ki te 4-5i.

$$x=\frac{\left(-2-6i\right)y+\left(-12-7i\right)}{4-5i}$$

Whakawehe -12-7i+\left(-2-6i\right)y ki te 4-5i.

$$x=\left(\frac{22}{41}-\frac{34}{41}i\right)y+\left(-\frac{13}{41}-\frac{88}{41}i\right)$$

Whakaoti mō y

$$y=\left(\frac{11}{20}+\frac{17}{20}i\right)x+\left(-\frac{33}{20}+\frac{29}{20}i\right)$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te x\left(4-5i\right) mai i ngā taha e rua.

$$y\left(2+6i\right)=-12-7i-x\left(4-5i\right)$$

Whakareatia te -1 ki te 4-5i, ka -4+5i.

$$y\left(2+6i\right)=-12-7i+\left(-4+5i\right)x$$

He hanga arowhānui tō te whārite.

$$\left(2+6i\right)y=\left(-4+5i\right)x+\left(-12-7i\right)$$

Whakawehea ngā taha e rua ki te 2+6i.

$$\frac{\left(2+6i\right)y}{2+6i}=\frac{\left(-4+5i\right)x+\left(-12-7i\right)}{2+6i}$$

Mā te whakawehe ki te 2+6i ka wetekia te whakareanga ki te 2+6i.

$$y=\frac{\left(-4+5i\right)x+\left(-12-7i\right)}{2+6i}$$

Whakawehe -12-7i+\left(-4+5i\right)x ki te 2+6i.

$$y=\left(\frac{11}{20}+\frac{17}{20}i\right)x+\left(-\frac{33}{20}+\frac{29}{20}i\right)$$