Whakaoti i te x*(y+2)*(y-3)=-12

$$x \times (y+2) \times (y-3)=-12$$

Whakaoti mō x

$$x=-\frac{12}{\left(y-3\right)\left(y+2\right)}$$

$$y\neq -2\text{ and }y\neq 3$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te x ki te y+2.

$$\left(xy+2x\right)\left(y-3\right)=-12$$

Whakamahia te āhuatanga tuaritanga hei whakarea te xy+2x ki te y-3 ka whakakotahi i ngā kupu rite.

$$xy^{2}-xy-6x=-12$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(y^{2}-y-6\right)x=-12$$

Whakawehea ngā taha e rua ki te y^{2}-y-6.

$$\frac{\left(y^{2}-y-6\right)x}{y^{2}-y-6}=-\frac{12}{y^{2}-y-6}$$

Mā te whakawehe ki te y^{2}-y-6 ka wetekia te whakareanga ki te y^{2}-y-6.

$$x=-\frac{12}{y^{2}-y-6}$$

Whakawehe -12 ki te y^{2}-y-6.

$$x=-\frac{12}{\left(y-3\right)\left(y+2\right)}$$

Whakaoti mō y (complex solution)

$$y=\frac{\sqrt{x\left(25x-48\right)}+x}{2x}$$

$$y=\frac{-\sqrt{x\left(25x-48\right)}+x}{2x}\text{, }x\neq 0$$

Whakaoti mō y

$$y=\frac{\sqrt{x\left(25x-48\right)}+x}{2x}$$

$$y=\frac{-\sqrt{x\left(25x-48\right)}+x}{2x}\text{, }x<0\text{ or }x\geq \frac{48}{25}$$