Whakaoti i te x*(x+2)+06=x*x+1/5

$$x \times (x+2)+06=x \times x+ \frac{ 1 }{ 5 }$$

Whakaoti mō x

$$x=\frac{1}{10}=0.1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia te x ki te x, ka x^{2}.

$$x\left(x+2\right)+0\times 6=x^{2}+\frac{1}{5}$$

Whakamahia te āhuatanga tohatoha hei whakarea te x ki te x+2.

$$x^{2}+2x+0\times 6=x^{2}+\frac{1}{5}$$

Whakareatia te 0 ki te 6, ka 0.

$$x^{2}+2x+0=x^{2}+\frac{1}{5}$$

Ko te tau i tāpiria he kore ka hua koia tonu.

$$x^{2}+2x=x^{2}+\frac{1}{5}$$

Tangohia te x^{2} mai i ngā taha e rua.

$$x^{2}+2x-x^{2}=\frac{1}{5}$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$2x=\frac{1}{5}$$

Whakawehea ngā taha e rua ki te 2.

$$x=\frac{\frac{1}{5}}{2}$$

Tuhia te \frac{\frac{1}{5}}{2} hei hautanga kotahi.

$$x=\frac{1}{5\times 2}$$

Whakareatia te 5 ki te 2, ka 10.

$$x=\frac{1}{10}$$