Whakaoti i te x*(x+2)+0.6=x*x+1/5

$$x \times (x+2)+0.6=x \times x+ \frac{ 1 }{ 5 }$$

Whakaoti mō x

$$x=-0.2$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia te x ki te x, ka x^{2}.

$$x\left(x+2\right)+0.6=x^{2}+\frac{1}{5}$$

Whakamahia te āhuatanga tohatoha hei whakarea te x ki te x+2.

$$x^{2}+2x+0.6=x^{2}+\frac{1}{5}$$

Tangohia te x^{2} mai i ngā taha e rua.

$$x^{2}+2x+0.6-x^{2}=\frac{1}{5}$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$2x+0.6=\frac{1}{5}$$

Tangohia te 0.6 mai i ngā taha e rua.

$$2x=\frac{1}{5}-0.6$$

Me tahuri ki tau ā-ira 0.6 ki te hautau \frac{6}{10}. Whakahekea te hautanga \frac{6}{10} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$2x=\frac{1}{5}-\frac{3}{5}$$

Tā te mea he rite te tauraro o \frac{1}{5} me \frac{3}{5}, me tango rāua mā te tango i ō raua taurunga.

$$2x=\frac{1-3}{5}$$

Tangohia te 3 i te 1, ka -2.

$$2x=-\frac{2}{5}$$

Whakawehea ngā taha e rua ki te 2.

$$x=\frac{-\frac{2}{5}}{2}$$

Tuhia te \frac{-\frac{2}{5}}{2} hei hautanga kotahi.

$$x=\frac{-2}{5\times 2}$$

Whakareatia te 5 ki te 2, ka 10.

$$x=\frac{-2}{10}$$

Whakahekea te hautanga \frac{-2}{10} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$x=-\frac{1}{5}$$