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x \sqrt{40} + 3 \cdot 0.9975640502598242 = 70
Evaluate trigonometric functions in the problem
x\times 2\sqrt{10}+3\times 0.9975640502598242=70
Tauwehea te 40=2^{2}\times 10. Tuhia anō te pūtake rua o te hua \sqrt{2^{2}\times 10} hei hua o ngā pūtake rua \sqrt{2^{2}}\sqrt{10}. Tuhia te pūtakerua o te 2^{2}.
x\times 2\sqrt{10}+2.9926921507794726=70
Whakareatia te 3 ki te 0.9975640502598242, ka 2.9926921507794726.
x\times 2\sqrt{10}=70-2.9926921507794726
Tangohia te 2.9926921507794726 mai i ngā taha e rua.
x\times 2\sqrt{10}=67.0073078492205274
Tangohia te 2.9926921507794726 i te 70, ka 67.0073078492205274.
2\sqrt{10}x=67.0073078492205274
He hanga arowhānui tō te whārite.
\frac{2\sqrt{10}x}{2\sqrt{10}}=\frac{67.0073078492205274}{2\sqrt{10}}
Whakawehea ngā taha e rua ki te 2\sqrt{10}.
x=\frac{67.0073078492205274}{2\sqrt{10}}
Mā te whakawehe ki te 2\sqrt{10} ka wetekia te whakareanga ki te 2\sqrt{10}.
x=\frac{335036539246102637\sqrt{10}}{100000000000000000}
Whakawehe 67.0073078492205274 ki te 2\sqrt{10}.