Whakaoti i te xdiv(x^2+8x)

$$x \div ( { x }^{ 2 } +8x)$$

Aromātai

$$\frac{1}{x+8}$$

Ngā Hipanga Rongoā Poto

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea.

$$\frac{x}{x\left(x+8\right)}$$

Me whakakore tahi te x i te taurunga me te tauraro.

$$\frac{1}{x+8}$$

Kimi Pārōnaki e ai ki x

$$-\frac{1}{\left(x+8\right)^{2}}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Otinga

Mō ngā pānga e rua e taea ana te pārōnaki, ko te pārōnaki o te otinga o ngā pānga e rua ko te tauraro whakareatia ki te pārōnaki o te taurunga tango i te taurunga whakareatia ki te pārōnaki o te tauraro, ā, ka whakawehea te katoa ki te tauraro kua pūruatia.

$$\frac{\left(x^{2}+8x^{1}\right)\frac{\mathrm{d}}{\mathrm{d}x}(x^{1})-x^{1}\frac{\mathrm{d}}{\mathrm{d}x}(x^{2}+8x^{1})}{\left(x^{2}+8x^{1}\right)^{2}}$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{\left(x^{2}+8x^{1}\right)x^{1-1}-x^{1}\left(2x^{2-1}+8x^{1-1}\right)}{\left(x^{2}+8x^{1}\right)^{2}}$$

Whakarūnātia.

$$\frac{\left(x^{2}+8x^{1}\right)x^{0}-x^{1}\left(2x^{1}+8x^{0}\right)}{\left(x^{2}+8x^{1}\right)^{2}}$$

Whakareatia x^{2}+8x^{1} ki te x^{0}.

$$\frac{x^{2}x^{0}+8x^{1}x^{0}-x^{1}\left(2x^{1}+8x^{0}\right)}{\left(x^{2}+8x^{1}\right)^{2}}$$

Whakareatia x^{1} ki te 2x^{1}+8x^{0}.

$$\frac{x^{2}x^{0}+8x^{1}x^{0}-\left(x^{1}\times 2x^{1}+x^{1}\times 8x^{0}\right)}{\left(x^{2}+8x^{1}\right)^{2}}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$\frac{x^{2}+8x^{1}-\left(2x^{1+1}+8x^{1}\right)}{\left(x^{2}+8x^{1}\right)^{2}}$$

Whakarūnātia.

$$\frac{x^{2}+8x^{1}-\left(2x^{2}+8x^{1}\right)}{\left(x^{2}+8x^{1}\right)^{2}}$$

Pahekotia ngā kīanga tau ōrite.

$$\frac{-x^{2}}{\left(x^{2}+8x^{1}\right)^{2}}$$

Mō tētahi kupu t, t^{1}=t.

$$\frac{-x^{2}}{\left(x^{2}+8x\right)^{2}}$$