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Whakaoti mō x
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t^{2}-5t+4=0
Whakakapia te t mō te x^{2}.
t=\frac{-\left(-5\right)±\sqrt{\left(-5\right)^{2}-4\times 1\times 4}}{2}
Ka taea ngā whārite katoa o te momo ax^{2}+bx+c=0 te whakaoti mā te ture pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Whakakapia te 1 mō te a, te -5 mō te b, me te 4 mō te c i te ture pūrua.
t=\frac{5±3}{2}
Mahia ngā tātaitai.
t=4 t=1
Whakaotia te whārite t=\frac{5±3}{2} ina he tōrunga te ±, ina he tōraro te ±.
x=2 x=-2 x=1 x=-1
I te mea ko x=t^{2}, ka riro ngā otinga mā te arotake i te x=±\sqrt{t} mō ia t.