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Whakaoti mō x
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Tohaina

x^{4}-10x^{2}+9=0
Me tāpiri te 9 ki ngā taha e rua.
t^{2}-10t+9=0
Whakakapia te t mō te x^{2}.
t=\frac{-\left(-10\right)±\sqrt{\left(-10\right)^{2}-4\times 1\times 9}}{2}
Ka taea ngā whārite katoa o te momo ax^{2}+bx+c=0 te whakaoti mā te ture pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Whakakapia te 1 mō te a, te -10 mō te b, me te 9 mō te c i te ture pūrua.
t=\frac{10±8}{2}
Mahia ngā tātaitai.
t=9 t=1
Whakaotia te whārite t=\frac{10±8}{2} ina he tōrunga te ±, ina he tōraro te ±.
x=3 x=-3 x=1 x=-1
I te mea ko x=t^{2}, ka riro ngā otinga mā te arotake i te x=±\sqrt{t} mō ia t.